WebJul 22, 2013 · On Windows the timer overflow problem in usually solved (in games) with using QueryPerformanceCounter () functions instead of GetTickCount (): double GetCycles () const { LARGE_INTEGER T1; QueryPerformanceCounter ( &T1 ); return static_cast ( T1.QuadPart ); } Web我们的语音平台程序,需要运行在大线路并发环境,要求有很高的性能。因为是多线程程序,在几百上千个线程同时加载脚本的时候,千军万马过独木桥,往往导致极大的CPU开销,比较好的办法就是在每个加载线程内对CPU占用进行判断,如果占用率小于某个值,就继续运行,否则就Sleep(),等候CPU ...
Release runs slower than debug build?
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DWord - What does DWord stand for? The Free Dictionary
WebDec 19, 2014 · This is because unsigned arithmetic overflow is well-defined in C, and wrapping behavior does exactly what we want. DWORD t1, t2; DWORD difference; t1 = … WebOct 11, 2012 · DWORD t1 = GetTickCount (); double sum = 0.0; vector< shared_ptr< thread > > threads; for ( unsigned i = 0; i < threadCount; ++i ) threads.push_back ( make_shared< thread > ( &ThreadProc, threadData ) ); for ( unsigned i = 0; i < threadData.size (); ++i ) { threads->join (); sum += threadData->value; } Websimulates it by using.....GetTickCount, with the result that the above "if" condition could fail after 49.7 days. For that I still have to use DWORDs instead of qwords and cast the subtraction to DWORD (so that the rollback doesn't matter as long as the WaitTime above is less than $ffffffff) BEFORE (with gettickcount): var PreviousTick:DWORD; import from printer/scanner